Monthly Math Contest |
Here is your chance to have a little fun and get a little recognition! Each month, the American Society of Mathematics sends a new problem to Dr. Koo. The first student to submit a correct answer will be the winner for the month, and have their name posted on the Department of Mathematical Sciences web page. The top problem solver for the year will be invited to attend the US National Collegiate Mathematics Championship in Madison, Wisconsin.
Rules:
Write your solution clearly and show all work.
Take your solution to the Secretary, Math Office Room 227,with name, date and time.
Include your name, contact information, date and time of submission.
The first correct solution will be the winner for the month.
All correct solutions will be recognized. Names posted on Math- Sciences Webpage.
A new problem will be posted the first week of each month during the spring and fall semesters.
The top problem solver for the year will be invited to attend the US National Collegiate Mathematics Championship, to be held in Madison, Wisconsin 2008.
Questions relating to this competition can be directed to Reginald Koo, at regk@usca.edu.
Find the value of the sum
Submit solutions to Math Dept secretary, include date and time submitted.
Deadline is Wednesday April 30, 2008 at 4.00 pm.
Derivative
Calculate the derivative with respect to x of the function
y = xx x .
Deadline for solutions is by March 31, 2008 at 4.00 p.m.
Winners: First Place: Behzad Torkian
A logarithmic equation.
Solve the equation
(ln x)2 − 2.5(ln x)(ln(4x − 5)) + (ln(4x − 5))2 = 0,
where x and all expressions in the equation are real.
Deadline for solutions is by Feb 28, 2008 at 4.00 p.m.
Consider the number 12355699. If we write each of the digits in this number
on separate slips of paper, put them in a bowl, and draw three of the numbers
at random, without replacement, what is the probability that the sum of the
numbers drawn will be even?
Deadline for submission of solution: 30 Nov at 4.00 p.m.
October 2007 PROBLEM :   6 DVDS   Julio has 6 favorite DVDs. If each DVD is 20 minutes long and Julio wants to watch all 6 DVDs over and over in every conceivable order, how long (in hours) will it take him to accomplish this? He will, for example, watch all 6 in a row in one order and then watch the same 6 in a different order, repeating this until all possible orders are achieved.
Solution to October 2007 Problem. There are 6! = 720 different orders of the DVDs. Each order requires 6·20 = 120 minutes or 2 hours to watch. Watching all possible orders then requires 720 · 2 = 1440 hours.
Winners: First Place: Brian Staples Other correct solutions: Matthew Coffin, Mark Woodhams.